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DGD::channelbuf
can't be used to make output. After all, it is derived from std::streambuf which is a kind of memory buffer. There must be a stream. The DGD::channel
is such a stream. Everything which was told about formatting is also true for DGD::channel. If fact, it has all formatting-related methods as DGD::channelbuf has.
There is a number of things which differ DGD::channel from std::ostream: Generated on Thu Aug 10 16:48:29 2006 for DGD Library by 1.3
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